Exams › JEE Main › Maths
Let M and m be the maximum and minimum values of y/x over all real pairs (x, y) satisfying (x - 3)² + (y - 3)² = 6. Find M + m.
- 6
- 3
- 2
- 9
Correct answer: 6
Solution
Tangency gives 3k² - 18k + 3 = 0 whose roots are M and m, so by Vieta's, M + m = 18/3 = 6.
Related JEE Main Maths questions
⚔️ Practice JEE Main Maths free + battle 1v1 →