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Let k1 = 6^(2*log₆(5)) + (2^(log₂(3)) * 3^(2*log₃(2))) and k2 = (3^(1/2))^(12*log₃(2)) + 49^(log₇(3)). Find k1 + k2.

1. 100
2. 108
3. 110
4. 120

Correct answer: 110

Solution

k1 = 25 + 3*4 = 37 and k2 = 64 + 9 = 73, giving k1 + k2 = 110.

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