Exams › JEE Main › Maths
For real numbers a, b, c (all non-zero), suppose a² + b² + c² = ab + bc + ca. If the value of (b+c)/a + (a+c)/b + (a+b)/c is denoted by lambda, find the value of lambda.
- 2
- 4
- 6
- 8
Correct answer: 6
Solution
The condition implies a = b = c (since each squared difference must be zero); substituting gives each term (b+c)/a = 2, so lambda = 2 + 2 + 2 = 6.
Related JEE Main Maths questions
- If x is a real number satisfying x + 1/x = 3, find all possible values of x² - 1/x².
- The equation sqrt(x + 1) - sqrt(x - 1) = sqrt(4x - 1) has how many real solutions?
- Let A be the set {(n, 2n): n ∈ N} and let B be the set {(2n, 3n): n ∈ N}. What is the intersection A ∩ B?
- Let set A contain 3 elements and set B contain 6 elements. Then the cardinality of their union must satisfy
- Given the sets A = {1, 2, 5} and B = {3, 4, 5, 9}, what is A ∩ B?
- At a conference with 100 attendees, 29 are Indian women and 23 are Indian men. Among the Indian attendees, 4 are doctors, and 24 are either men or doctors. If there are no foreign doctors, how many foreigners and how many women doctors are present at the conference?
⚔️ Practice JEE Main Maths free + battle 1v1 →