Exams › JEE Main › Maths
Find the area (in square units) of the region enclosed by the curve defined by |x + y| + |x - y| = 11.
- 121
- 144
- 100
- 169
Correct answer: 121
Solution
The relation |x + y| + |x - y| = 2*max(|x|, |y|) = 11 gives max(|x|, |y|) = 5.5, which is a square with side 11 centred at the origin. Its area is 11² = 121.
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