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The area (in square units) bounded by the curves y = √x, 2y − x + 3 = 0, X-axis and lying in the first quadrant is
- 18 sq. units
- 27/4 sq. units
- 9 sq. units
- 36 sq. units
Correct answer: 9 sq. units
Solution
The area is determined by finding the points of intersection between the curves and calculating the integral of the upper curve minus the lower curve over the defined interval. In this case, the area bounded by y = √x and the line 2y - x + 3 = 0 in the first quadrant results in an area of 9 square units.
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