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The area enclosed by the curves y = x², y = x³, x = 0 and x = p, where p > 1, is 1/6. The p equals
- 8/3
- 16/3
- 2
- 4/3
Correct answer: 4/3
Solution
The area between the curves y = x² and y = x³ from x = 0 to x = p can be calculated using integration. Setting up the integral and solving for p when the area equals 1/6 leads to the conclusion that p must be 4/3.
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