Exams › JEE Main › Maths
Consider the following planes \(P: x+y-2z+7=0\) \(Q: x+y+2z+2=0\) \(R: 3x+3y-6z-11=0\)
- P and R are perpendicular
- Q and R are perpendicular
- P and Q are parallel
- P and R are parallel
Correct answer: P and R are parallel
Solution
Planes P and R are parallel because their normal vectors, derived from the coefficients of x, y, and z in their equations, are scalar multiples of each other, indicating that they do not intersect.
Related JEE Main Maths questions
- A line makes equal angles \(\alpha\), \(\beta\), and \(\gamma\) with the positive directions of the coordinate axes. If \(\theta\) satisfies \[ \cos\theta=\frac{\cos^2\alpha+\cos^2\beta+\cos^2\gamma}{\sin^2\alpha+\sin^2\beta+\sin^2\gamma}, \] then what is the value of \(\theta\)?
- Consider the following two statements: Statement 1: If \(A\), \(B\), and \(C\) are points with position vectors \(\mathbf{a}=2\hat{i}+\hat{j}+\hat{k}\), \(\mathbf{b}=3\hat{i}-\hat{j}+3\hat{k}\), and \(\mathbf{c}=\hat{i}+7\hat{j}-5\hat{k}\), then the figure \(OABC\) forms a tetrahedron. Statement 2: If the position vectors \(\mathbf{a}\), \(\mathbf{b}\), and \(\mathbf{c}\) of points \(A\), \(B\), and \(C\) are non-coplanar, then \(OABC\) is a tetrahedron, where \(O\) denotes the origin. Choose the correct option.
- Find the locus of a point whose sum of the squares of its perpendicular distances from the planes \(x+y+z=0\), \(x-z=0\), and \(x-2y+z=0\) equals 19.
- A moving plane always contains the fixed point \((1,2,3)\). The set of points that are the perpendicular projections of the origin onto this plane is described by
- The direction cosines \(l,m,n\) of one of the two lines satisfying the relations \(l-5m+3n=0\) and \(7l^2+5m^2-3n^2=0\) are
- A sphere is given by the equation \(x^2+y^2+z^2-10z=0\). If one endpoint of a diameter is \((-3,4,5)\), then what are the coordinates of the opposite endpoint?
⚔️ Practice JEE Main Maths free + battle 1v1 →