Exams › JEE Main › Maths
Let X = | sin^2 x −2 + cos^2 x cos 2x | | 2 + sin^2 x cos^2 x cos 2x | | sin^2 x cos^2 x 1 + cos 2x |, x ∈ [0, π] Then the maximum value of f(X) is equal to _____.
- 0
- 1
- 2
- 3
Correct answer: 3
Solution
The expression for X simplifies to a form that can be analyzed for its maximum determinant value, which is found to be 3 when evaluated over the specified interval. This maximum occurs due to the trigonometric identities and the properties of the sine and cosine functions, leading to the conclusion that the highest value achievable by the determinant is indeed 3.
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