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For the four circles M, N, O and P, following four equations are given : Circle M : x² + y² = 1 Circle N : x² + y² − 2x = 0 Circle O : x² + y² − 2x − 2y + 1 = 0 Circle P : x² + y² − 2y = 0 If the centre of circle M is joined with centre of the circle N, further centre of circle N is joined with centre of circle O, centre of circle O is joined with the centre of circle P and lastly, centre of circle P is joined with centre of circle M, then these lines from the sides of a :
- Rhombus
- Square
- Rectangle
- Parallelogram
Correct answer: Square
Solution
The centers of the circles form a square because the distances between adjacent centers are equal and the angles between the lines connecting them are right angles, which is characteristic of a square.
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