Exams › JEE Main › Maths
Choose the correct statement about two circles whose equations are given below : x^2 + y^2 - 10x - 10y + 41 = 0 x^2 + y^2 - 22x - 10y + 137 = 0
- circles have same centre
- circles have no meeting point
- circles have only one meeting point
- circles have two meeting points
Correct answer: circles have no meeting point
Solution
The two circles do not intersect because the distance between their centers is greater than the sum of their radii, indicating that they are separate from each other.
Related JEE Main Maths questions
- An ellipse has its two foci 10 units apart, and the length of its latus rectum is 15. If its axes are taken as the coordinate axes, which equation represents the ellipse?
- On the segment joining \(A(0,0)\) and \(B(3a,0)\), points \(P\) and \(Q\) are chosen such that \(AP=PQ=QB\). Three circles are then constructed with \(AP\), \(PQ\), and \(QB\) as their respective diameters. If a point \(S\) is such that the sum of the squares of the tangents drawn from \(S\) to these three circles is \(b^2\), then the locus of \(S\) is
- Find the coordinates of the midpoint of the chord cut by the circle \(x^2+y^2+4x-2y-3=0\) on the line \(y=x+2\).
- A hyperbola has a transverse axis of length \(2\sin\theta\) and is confocal with the ellipse \(3x^2+4y^2=12\). Its equation is
- Three points \(E\), \(F\), and \(G\) are chosen on the parabola \(y^2=4ax\) such that their y-coordinates form a geometric progression. The point where the tangents at \(E\) and \(G\) meet lies on the
- In the parabola \(x^2-2x+y-2=0\), let \(AB\) be a focal chord and \(S\) be the focus. If \(AS=l_1\), then what is the value of \(BS\)?
⚔️ Practice JEE Main Maths free + battle 1v1 →