Exams › JEE Main › Maths
If | a − b − c 2a 2a | | 2b b − c − a 2b | = (a + b + c)(x + a + b + c)^2, x ≠ 0 and a + b + c ≠ 0, then x is equal to : | 2c 2c c − a − b |
- −2(a + b + c)
- 2(a + b + c)
- abc
- −(a + b + c)
Correct answer: 2(a + b + c)
Solution
The correct option is 2(a + b + c) because when the determinant of the left matrix is calculated and simplified, it results in a factor that includes (a + b + c), leading to the conclusion that x must be twice that sum to maintain equality.
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