Let A = {x : x is 3-digit number} B = {x : x = 9k + 2, k ∈ I} and C = {x : x = 9k + k, k ∈ I, l ∈ I, 0

Question

Let A = {x : x is 3-digit number} B = {x : x = 9k + 2, k ∈ I} and C = {x : x = 9k + k, k ∈ I, l ∈ I, 0 < l < 9} for some l (0 < l < 9) If the sum of all the elements of the set A ∩ (B ∪ C) is 274 × 400, then ℓ is equal to

Accepted Answer

3. The correct option is 3 because the intersection of set A with the union of sets B and C yields a specific set of 3-digit numbers that can be expressed in the forms defined by B and C. The sum of these numbers aligns with the given total of 274 × 400, which indicates that the value of l must be 3 to satisfy the conditions of the problem.

Let A = {x : x is 3-digit number} B = {x : x = 9k + 2, k ∈ I} and C = {x : x = 9k + k, k ∈ I, l ∈ I, 0 < l < 9} for some l (0 < l < 9) If the sum of all the elements of the set A ∩ (B ∪ C) is 274 × 400, then ℓ is equal to

Solution

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