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Let \[f(x)=\lim_{n\to\infty}\frac{\tan(\pi x^2)+(x+1)^n\sin x}{x^2+(x+1)^n}.\] Then which statement is true about the function at \(x=0\)?
- The function is continuous at \(x=0\).
- The function is differentiable at \(x=0\).
- The function is continuous at \(x=0\) but not differentiable there.
- None of the above.
Correct answer: The function is continuous at \(x=0\).
Solution
The function is continuous at x=0 because as n approaches infinity, the term (x+1)^n dominates both the numerator and denominator, leading to a limit that exists and equals a finite value when evaluated at x=0.
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