Exams › JEE Main › Maths
For the linear system x1 + 2x2 + 3x3 = 6 x1 + 3x2 + 5x3 = 9 2x1 + 5x2 + ax3 = b if it is consistent and admits infinitely many solutions, then which statement must be true?
- a = 8, and b may be any real number
- b = 15, and a may be any real number
- a belongs to R \ {8} and b belongs to R \ {15}
- a = 8, b = 15
Correct answer: a = 8, and b may be any real number
Solution
The system must have a specific relationship between the coefficients for it to be consistent with infinitely many solutions. Setting a = 8 ensures that the third equation is a linear combination of the first two, while b can vary freely, allowing for infinite solutions.
Related JEE Main Maths questions
- In a triangle $ABC$, if the determinant $\begin{vmatrix}\sin A & \sin^2 A\\ \sin B & \sin^2 B\\ \sin C & \sin^2 C\end{vmatrix}=0$, then the triangle must be
- If $[\,\cdot\,]$ represents the greatest integer less than or equal to a real number, and $-1\le x<0$, $0\le y<1$, $1\le z<2$, then the determinant \[ \begin{vmatrix} [x] & [y] & [z] \\ [x+1] & [y+1] & [z] \\ [x] & [y] & [z]+1 \end{vmatrix} \] is equal to:
- Let $x$, $y$, and $z$ be complex numbers. If $\Delta$ denotes the determinant of the matrix \[ \begin{bmatrix} 0 & -y & -z\\ y & 0 & -x\\ z & x & 0 \end{bmatrix}, \] then $\Delta$ is
- For the linear system \[ \begin{aligned} x_1+2x_2+3x_3&=6\\ x_1+3x_2+5x_3&=9\\ 2x_1+5x_2+ax_3&=b \end{aligned} \] if it is consistent and admits infinitely many solutions, then which statement must be true?
- For which value(s) of $x$ does the determinant of the matrix \[ \begin{vmatrix} 1 & x-3 & (x-3)^2\\ 1 & x-4 & (x-4)^2\\ 1 & x-5 & (x-5)^2 \end{vmatrix} \] become zero?
- Let $\Delta_r$ denote the determinant \[ \Delta_r=\begin{vmatrix} \binom{m}{r} & 1 & 1\\ m^2-1 & 2^m & m+1\\ \sin^2(m^2) & \sin^2(m) & \sin^2(m+1) \end{vmatrix}. \] Then the value of $\sum_{r=0}^{m} \Delta_r$ is
⚔️ Practice JEE Main Maths free + battle 1v1 →