Exams › JEE Main › Maths
Evaluate the sum of the first n terms of the series 1/(1+1^2+1^4) + 2/(1+2^2+2^4) + 3/(1+3^2+3^4) + ...
- (n^2+n-1)/(2(n^2+n+1))
- (n^2+n)/(2(n^2+n+1))
- (n^2-n+1)/(n^2+n+1)
- (n^2-n)/(2(n^2+n+1))
Correct answer: (n^2-n+1)/(n^2+n+1)
Solution
The correct option simplifies the series by recognizing the pattern in the denominators and numerators, leading to a formula that accurately represents the sum of the first n terms in a consistent manner.
Related JEE Main Maths questions
⚔️ Practice JEE Main Maths free + battle 1v1 →