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The area enclosed by the curves y = |sin x + cos x| and y = |cos x - sin x| and the lines x = 0, x = π/2 is:
- 2√2(√2 - 1)
- 2(√2 + 1)
- 4(√2 - 1)
- 2√2(√2 + 1)
Correct answer: 2√2(√2 - 1)
Solution
Over [0,pi/2] the enclosed area between y=|sin x+cos x| and y=|cos x-sin x| evaluates to 2*sqrt(2)*(sqrt(2)-1) ~ 1.172 square units.
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