Exams › JEE Main › Maths
If the coefficients of x² and x³ are both zero, in the expansion of the expression (1 + ax + bx²)(1 − 3x)¹⁵ in powers of x, then the ordered pair (a,b) is equal to:
- (28, 88)
- (28, 315)
- (-21, 714)
- (-54, 315)
Correct answer: (28, 315)
Solution
The coefficients of x² and x³ in the expansion must be zero, which leads to a system of equations involving a and b. Solving these equations reveals that the only values that satisfy both conditions are a = 28 and b = 315.
Related JEE Main Maths questions
⚔️ Practice JEE Main Maths free + battle 1v1 →