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ExamsJEE MainMaths

The number of natural numbers less than 7,000 which can be formed by using the digits 0, 1, 3, 7, 9 (repetition of digits allowed) is equal to:

  1. 372
  2. 375
  3. 250
  4. 374

Correct answer: 374

Solution

To find the total number of natural numbers less than 7,000 using the digits 0, 1, 3, 7, and 9, we consider the cases based on the number of digits. For 1-digit numbers, we have 4 options (1, 3, 7, 9). For 2-digit numbers, the first digit has 4 options (1, 3, 7, 9) and the second digit has 5 options (including 0). For 3-digit numbers, the first digit again has 4 options, while the other two digits have 5 options each. For 4-digit numbers, the first digit can only be 1, 3, or 6 (to keep it under 7,000), giving us 3 options, and the remaining three digits can be any of the 5 digits. Adding all these cases together gives a total of 374 valid numbers.

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