Exams › JEE Main › Maths
The area (in sq. units) of the region {x ∈ R: x ≥ 0, y ≥ 0, y ≥ x - 2 and y ≤ √x}, is
- 13/3
- 10/3
- 5/3
- 8/3
Correct answer: 10/3
Solution
The area is determined by the intersection of the lines and curves defined by the inequalities, specifically the line y = x - 2 and the curve y = √x. By calculating the area between these boundaries in the first quadrant, we find that the total area is 10/3 square units.
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