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The distance of the point (1, 0, 2) from the point of intersection of the line (x − 2)/3 = (y + 1)/4 = (z − 2)/12 and the plane x − y + z = 16, is

1. 3√21
2. 13
3. 2√14
4. 8

Correct answer: 13

Solution

To find the distance from the point (1, 0, 2) to the intersection of the given line and plane, we first determine the coordinates of the intersection point. After calculating, we find that the intersection point is (5, 1, 10). The distance formula is then applied, yielding a distance of 13, confirming option B as the correct answer.

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