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The equation of the plane containing the line 2x − 5y + z = 3; x + y + 4z = 5, and parallel to the plane, x + 3y + 6z = 1, is:
- x + 3y + 6z = 7
- 2x + 6y + 12z = −13
- 2x + 6y + 12z = 13
- x + 3y + 6z = −7
Correct answer: x + 3y + 6z = 7
Solution
The correct option is right because it maintains the same normal vector as the given parallel plane, ensuring that it is parallel, while also satisfying the condition of passing through the line defined by the two equations.
Related JEE Main Maths questions
- Consider the following two statements:
Statement 1: If A, B and C are points with position vectors a = 2î + ĵ + k̂, b = 3î - ĵ + 3k̂ and c = î + 7ĵ - 5k̂, then the figure OABC forms a tetrahedron.
Statement 2: If the position vectors a, b and c of points A, B and C are non-coplanar, then OABC is a tetrahedron, where O denotes the origin.
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