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What is the least distance between the plane 12x + 4y + 3z = 327 and the sphere x² + y² + z² + 4x - 2y - 6z = 155?

1. 39
2. 26
3. 11 4/13
4. 13

Correct answer: 13

Solution

The least distance between the plane and the sphere is determined by finding the distance from the center of the sphere to the plane and then subtracting the radius of the sphere. In this case, the calculations yield a minimum distance of 13 units.

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