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Given that dy/dx = y + 3 > 0 and y(0) = 2, what is the value of y(ln 2)?
- 5
- 13
- -2
- 7
Correct answer: 7
Solution
The differential equation dy/dx = y + 3 indicates that the rate of change of y is always positive when y is above -3, which is the case here since y(0) = 2. Solving the equation with the initial condition leads to the value of y(ln 2) being 7.
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