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If x^m · yⁿ = (x + y)^(m+n), then dy/dx is
- y/x
- (x + y)/(xy)
- xy
- x/y
Correct answer: y/x
Solution
Taking logs: m ln x + n ln y = (m+n) ln(x+y). Differentiating and simplifying gives dy/dx=y/x.
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