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Suppose f(x) is differentiable at x = 1 and lim(h→0) [1/h] f(1 + h) = 5, then f'(1) equals
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Correct answer: 5
Solution
For lim_{h->0} f(1+h)/h to be finite, f(1)=0. Then f(1+h)/h = [f(1+h)-f(1)]/h -> f'(1). Hence f'(1)=5.
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