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Let f: N→Y be a function defined as f(x)=4x+3 where Y={y∈N: y=4x+3 for some x∈N}. Then, the inverse of f(x) is

1. g(y)=(3y+4)/(3)
2. g(y)=4+(y+3)/(4)
3. g(y)=(y+3)/(4)
4. g(y)=(y-3)/(4)

Correct answer: g(y)=(y-3)/(4)

Solution

The correct option is right because to find the inverse of the function f(x) = 4x + 3, we need to solve for x in terms of y. Rearranging the equation gives y - 3 = 4x, which simplifies to x = (y - 3)/4, thus the inverse function is g(y) = (y - 3)/4.

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