Exams › JEE Main › Maths

In the expansion of (1 - x - x² + x³)⁶, what is the coefficient of x⁷?

1. -132
2. -144
3. 132
4. 144

Correct answer: -144

Solution

The coefficient of x⁷ in the expansion can be determined using the multinomial theorem, where we consider the different ways to select terms from the polynomial raised to the sixth power. The correct option, -144, arises from the specific combinations of terms that yield x⁷, accounting for the negative signs in the polynomial.

Related JEE Main Maths questions

• Let Pn = cosⁿ θ + sinⁿ θ. If Pn - Pn-2 = k Pn-4, then the value of k is:
• For any natural number n, the expression x^(2n - 1) + y^(2n - 1) is divisible by which of the following?
• For a natural number n, which of the following always divides the expression x^(n+1) + (x + 1)^(2n−1)?
• For a positive integer n, the expression 5^(2n+2) − 24n − 25 is divisible by which of the following?
• For every natural number n, the expression 41ⁿ − 14ⁿ is divisible by which of the following?
• Let C0, C1, C2,..., C15 denote the binomial coefficients in the expansion of (1 + x)¹⁵. Then the value of C1/C0 + C2/C1 + C3/C2 +... + C15/C14 is:

⚔️ Practice JEE Main Maths free + battle 1v1 →