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The number of integers greater than 6,000 that can be formed, using the digits 3, 5, 6, 7 and 8, without repetition, is:

1. 120
2. 72
3. 216
4. 192

Correct answer: 192

Solution

All 5-digit arrangements (5! = 120) exceed 6000. For 4-digit numbers > 6000 the leading digit must be 6, 7 or 8 (3 ways) and the rest 4*3*2 = 24, giving 72. Total = 120 + 72 = 192.

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