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If set A has 4 elements and set B has 2 elements, then how many subsets of the Cartesian product A × B contain at least 3 elements?
- 275
- 510
- 219
- 256
Correct answer: 219
Solution
A x B has 4*2 = 8 elements. Subsets of an 8-element set with at least 3 elements = 2^8 - C(8,0) - C(8,1) - C(8,2) = 256 - 1 - 8 - 28 = 219.
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