Correct answer: (0,1)∪(1,4)
f(x) = (a^2-3a+2)(cos2x)/4 + (a-1)x + sin1, so f'(x) = (a-1)[1 - (a-2)(sin2x)/2]. For no critical point f' must never be 0. Excluding a=1 (where f'==0), need |a-1| > |(a-1)(a-2)/2|, i.e. |a-2| < 2 -> 0<a<4. Removing a=1 gives (0,1) U (1,4).