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Determine the point on the parabola y = x² + 7x + 2 that lies nearest to the line y = 3x - 3.
- (-2,-8)
- (2,8)
- (-2,8)
- (2,-8)
Correct answer: (-2,-8)
Solution
The nearest point has tangent parallel to y=3x-3. dy/dx=2x+7=3 => x=-2, y=(-2)^2+7(-2)+2=-8. The point is (-2,-8).
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