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A line parallel to the x-axis passes through the point of intersection of the lines ax + 2by + 3b = 0 and bx - 2ay - 3a = 0, where (a, b) ≠ (0, 0). This line is
- below the x-axis at a distance of 3/2 units
- below the x-axis at a distance of 2/3 units
- above the x-axis at a distance of 3/2 units
- above the x-axis at a distance of 2/3 units
Correct answer: below the x-axis at a distance of 3/2 units
Solution
The correct option is right because the intersection of the given lines can be calculated, revealing that the y-coordinate of the intersection point is -3/2, which indicates that the line parallel to the x-axis at this point is indeed below the x-axis at a distance of 3/2 units.
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