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ExamsJEE MainMaths

A square has one diagonal lying on the line x = 2y. If one of its vertices is at (3, 0), then the equations of the two sides passing through this vertex are

  1. y - 3x + 9 = 0, 3y + x - 3 = 0
  2. y + 3x + 9 = 0, 3y + x - 3 = 0
  3. y - 3x + 9 = 0, 3y - x + 3 = 0
  4. y - 3x + 3 = 0, 3y + x + 9 = 0

Correct answer: y - 3x + 9 = 0, 3y + x - 3 = 0

Solution

The diagonal x=2y has slope 1/2; the sides through a vertex make 45 degrees with it, giving slopes (1/2+1)/(1-1/2)=3 and (1/2-1)/(1+1/2)=-1/3. Through (3,0): y-3x+9=0 and 3y+x-3=0 (these are perpendicular, as required).

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