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If the terms a1, a2, a3,..., an form an arithmetic progression and a4 - a7 + a10 = m, then the sum of the first 13 terms of the progression is:
- 10m
- 12m
- 13m
- 15m
Correct answer: 13m
Solution
For an AP, a4-a7+a10 = (a+3d)-(a+6d)+(a+9d) = a+6d = a7 = m. Sum of first 13 terms = 13/2*(2a+12d) = 13(a+6d) = 13m.
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