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If 10 white, 9 green, and 7 black balls are available, and balls of the same colour are identical, in how many distinct ways can one choose at least one ball?
- 880
- 629
- 630
- 879
Correct answer: 879
Solution
Identical balls of each colour: number of subsets choosing 0..10 white, 0..9 green, 0..7 black = 11*10*8 = 880; subtract the empty selection -> 879.
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