Exams › JEE Main › Maths
If the inequality (2m + x)/3 ≤ (4mx - 1)/2 has solution set x ≥ 3/4, what is the value of the parameter m?
- 7/10
- 9/10
- 9/11
- None of these
Correct answer: 9/10
Solution
(2m+x)/3 <= (4mx-1)/2 -> 4m+2x <= 12mx-3 -> x(12m-2) >= 4m+3 -> x >= (4m+3)/(12m-2). Setting (4m+3)/(12m-2) = 3/4 gives 16m+12 = 36m-6, so 20m = 18 and m = 9/10.
Related JEE Main Maths questions
⚔️ Practice JEE Main Maths free + battle 1v1 →