Exams › JEE Main › Maths
Given that the number of elements in set A is 4 and in set B is 3, and the Cartesian product A × B × C has 24 elements, what is the number of elements in set C?
- 288
- 1
- 12
- 2
Correct answer: 2
Solution
|A x B x C| = 4 * 3 * |C| = 24, so |C| = 24/12 = 2.
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