Exams › JEE Main › Maths

In a conflict, 70% of the fighters lost one eye, 80% lost an ear, 75% lost an arm, and 85% lost a leg. If x% of them lost all four of these parts, what is the least possible value of x?

1. 10
2. 12
3. 15
4. None of these

Correct answer: 10

Solution

The minimum percentage losing all four = 100 - [(100-70)+(100-80)+(100-75)+(100-85)] = 100 - (30+20+25+15) = 100 - 90 = 10. So the least value of x is 10.

Related JEE Main Maths questions

• Let A be the set {(n, 2n): n ∈ N} and let B be the set {(2n, 3n): n ∈ N}. What is the intersection A ∩ B?
• Let set A contain 3 elements and set B contain 6 elements. Then the cardinality of their union must satisfy
• Given the sets A = {1, 2, 5} and B = {3, 4, 5, 9}, what is A ∩ B?
• At a conference with 100 attendees, 29 are Indian women and 23 are Indian men. Among the Indian attendees, 4 are doctors, and 24 are either men or doctors. If there are no foreign doctors, how many foreigners and how many women doctors are present at the conference?
• Let X and Y be two non-empty sets, and let A be a non-empty set such that X ∩ A = Y ∩ A = A and X ∪ A = Y ∪ A. Which of the following must be true?
• If A and B are non-empty sets with A containing B, then which of the following is true?

⚔️ Practice JEE Main Maths free + battle 1v1 →