Exams › JEE Main › Maths › Mathematical Tools (Calculus)
1 questions with worked solutions.
Q1. If v = 3t² - 2t + 1, find the value of t for which dv/dt = 0.
Answer: 1/3
Differentiating v = 3t² - 2t + 1 gives dv/dt = 6t - 2. Setting 6t - 2 = 0 yields t = 1/3.