Exams › JEE Main › Maths › Circles / Coordinate Geometry
1 questions with worked solutions.
Answer: 72 cm
Let the two perpendicular diameters be the x- and y-axes with centre O at the origin. Let P = (x, y) lie on the circle, so x² + y² = r². The foot of perpendicular from P to the x-axis is A = (x, 0); to the y-axis is B = (0, y). Then OAPB is a rectangle, and its diagonal AB equals OP = sqrt(x² + y²) = r. So AB = r = 36 cm, hence diameter = 2r = 72 cm.