Exams › JEE Main › Maths › Algebra — Theory of Equations
1 questions with worked solutions.
Answer: 4
By Vieta's formulas, the elementary symmetric sums are a+b+c=2, ab+bc+ca=1, abc=1. Newton's identity gives pₙ=2pₙ₋₁-pₙ₋₂+pₙ₋₃. Starting from p₀=3, p₁=2, p₂=2, successive application yields p₃=5, p₄=10, p₅=17. Thus 4*17/17=4.