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Let A be the point of intersection of the lines L 1 : x 7 y 5 z 3 1 0 1       and L 2 : x 1 y 3 z 7 3 4 5      . Let B and C be the points on the lines L 1 and L 2 respectively such that AB = AC = 15 . Then the square of the area of the triangle ABC is:

1. 57
2. 63
3. 60
4. 54

Correct answer: 54

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