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Consider two sets A and B, each containing three numbers in A.P. let the su m and the product of the elements of A be 36 and p respectively and the sum and the product of the elements of B be 36 and q respectively. Let d and D be the common differences of AP's in A and B respectively such that D = d + 3, d > 0. If p q p q = 19 5 , then p – q is equal to
- 630
- 540
- 450
- 600
Correct answer: 540
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