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Let the three sides of a triangle are on the lines 4 x – 7 y + 10 = 0, x + y = 5 and 7 x + 4 y = 15. Then the distance of its orthocentre from the orthocent er of the triangle formed by the lines x = 0, y = 0 and x + y = 1 is
- 20
- 5
- 5
- 20
Correct answer: 5
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