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Considering the principal values of the in verse trigonometric functions, sin – 1 2 3 1 x 1 x 2 2           , – 1 2 < x < 2 1 , is equal to

1. 4  + sin – 1 x
2. 6  + sin – 1 x
3. 5 6  – sin – 1 x
4. 5 6   – sin – 1 x

Correct answer: 6  + sin – 1 x

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