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ExamsJEE MainGeneral

If C (diamond)  C(graphite) + X kJ mol – 1 C(diamond) + O 2 (g)  CO 2 (g) + Y kJ mo l – 1 C(graphite) + O 2 (g)  CO 2 (g) + Z kJ mol – 1 At constant temperature. Then

  1. X = Y + Z
  2. – X = Y + Z
  3. X = – Y + Z
  4. X = Y – Z

Correct answer: X = Y – Z

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