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Let y = y(x) be the solution of the differential equation cosx(log e (cosx)) 2 dy + (sinx –3ysinx log e (cosx))dx = 0, x ∈ ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ π 2 , 0 . If y ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ π 4 = 2 log 1 e − , then y ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ π 6 is :

1. ) 4 ( log ) 3 ( log 2 e e −
2. ) 3 ( log ) 4 ( log 1 e e −
3. – ) 4 ( log 1 e
4. ) 4 ( log ) 3 ( log 1 e e −

Correct answer: ) 4 ( log ) 3 ( log 1 e e −

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