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If f (x) = ∫ + ) x 1 ( x 1 4 / 1 4 / 1 dx, f (0) = – 6, then f

1. is equal to:
2. log e 2 + 2
3. 4(log e 2 – 2)
4. 2 – log e 2 (4) 4(log e 2 + 2)

Correct answer: log e 2 + 2

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