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CrCl 3 .xNH 3 can exist as a complex. 0.1 molal aqueous solution of this complex shows a depression in freezing point of 0.558ºC. Assuming 100% ionisation of this complex and coordination number of Cr is 6, the complex will be (Given K f = 1.86 K kg mol –1 )

1. [Cr(NH 3 ) 6 ] Cl 3
2. [Cr(NH 3 ) 4 Cl 2 ] Cl
3. [Cr(NH 3 ) 5 Cl] Cl 2
4. [Cr(NH 3 ) 3 Cl 3 ]

Correct answer: [Cr(NH 3 ) 5 Cl] Cl 2

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