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If the function f(x) = ⎪ ⎪ ⎪ ⎩ ⎪ ⎪ ⎪ ⎨ ⎧ > ⎟ ⎟ ⎠ ⎞ ⎜ ⎜ ⎝ ⎛ + + = < − + + 0 x , x k 2 x k 2 log x 2 0 x , 4 0 x }, x ) 1 k sin( x ) 1 k {sin( x 2 2 1 e 2 1 is continuous at x = 0, 2 2 2 1 k k + is equal to-

1. 8
2. 20
3. 5
4. 10

Correct answer: 10

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